G' can complete (3/4) of a job in 24 days, while 'G' and 'H' together can complete the same job in 16 days. Find the time taken by 'H' to complete 25% of the job alone.
ATQ, Time taken by 'G' to complete the whole job alone = 24×( 4/3)=32 days Let the total amount of work = LCM of 32 and 16 = 96 units Efficiency of 'G' =96/32 = 3 units per day Efficiency of (G + H) = 96/16= 6 units per day Efficiency of 'H' = 6−3 = 3 units per day Desired time = (0.25 × 96/3) = 8 days
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