Question
‘A’ can complete a work in 15 days and is 50% more
efficient than ‘B’. ‘A’ and ‘B’ start working together and ‘A’ leaves after 8 days. The rest of the work is completed by ‘B’ alone in ‘x’ days. Find the value of ‘x’.Solution
ATQ, Time taken by ‘B’ to complete the work = 1.5 × 15 = 22.5 days (round up to 23 days) Let the total work = 230 units Efficiency of ‘A’ = 230/15 = 15.33 units/day (round to 15 units/day) Efficiency of ‘B’ = 230/23 = 10 units/day Work completed by ‘A’ and ‘B’ in 8 days = (15 + 10) × 8 = 200 units Therefore, x = (230 – 200)/10 = 3 days
If a+1/a =9, then a5+1/a5 is equal to:
If a + (1/a) = 2, then find the value of (a5 + a3 + 6)/(7a – 5).
22% of ‘x’ is equal to 66% of ‘y’, then find the value of x: y.
If 3y-3/y=18 then find the value of y² +1/y²
If AB = x + 3, BC = 2x and AC = 4x − 5, then for what value of ‘x’ does B lie on AC?
Solve for x:
(2x − 1)/3 − (x − 4)/2 = 3
If √b + (1/√b) = 11, then find the value of b + (1/b).
If, 4x2 + y2 + 12x + 6y + 18 = 0, then find the value of (2x + y)/(y + 6x).
If ( p = 40 - q - r ) and ( pq + r(q + p) = 720 ), then find the value of ( p2 + q2 + r2).
Relevant for Exams:
