‘A’ can complete a work in 15 days and is 50% more efficient than ‘B’. ‘A’ and ‘B’ start working together and ‘A’ leaves after 8 days. The rest of the work is completed by ‘B’ alone in ‘x’ days. Find the value of ‘x’.
ATQ, Time taken by ‘B’ to complete the work = 1.5 × 15 = 22.5 days (round up to 23 days) Let the total work = 230 units Efficiency of ‘A’ = 230/15 = 15.33 units/day (round to 15 units/day) Efficiency of ‘B’ = 230/23 = 10 units/day Work completed by ‘A’ and ‘B’ in 8 days = (15 + 10) × 8 = 200 units Therefore, x = (230 – 200)/10 = 3 days
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