Question
βAβ can complete a work in 18 days and is 10% more
efficient than βBβ. βAβ and βBβ start the work together, but βAβ leaves after 15 days. The remaining work is completed by βBβ alone in βxβ days. Find the value of βxβ.Solution
ATQ, Time taken by βBβ to complete the work = 1.1 Γ 18 = 19.8 days (round up to 20 days) Let the total work = 180 units Efficiency of βAβ = 180/18 = 10 units/day Efficiency of βBβ = 180/20 = 9 units/day Work completed by βAβ and βBβ in 15 days = (10 + 9) Γ 15 = 285 units (exceeds total units, adjust to maximum possible, which is 180 units) Since the total work is completed in the given period, x = 0 days
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