‘A’ can complete a work in 18 days and is 10% more efficient than ‘B’. ‘A’ and ‘B’ start the work together, but ‘A’ leaves after 15 days. The remaining work is completed by ‘B’ alone in ‘x’ days. Find the value of ‘x’.
ATQ, Time taken by ‘B’ to complete the work = 1.1 × 18 = 19.8 days (round up to 20 days) Let the total work = 180 units Efficiency of ‘A’ = 180/18 = 10 units/day Efficiency of ‘B’ = 180/20 = 9 units/day Work completed by ‘A’ and ‘B’ in 15 days = (10 + 9) × 15 = 285 units (exceeds total units, adjust to maximum possible, which is 180 units) Since the total work is completed in the given period, x = 0 days
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