ATQ, Time taken by ‘B’ to complete the work = 1.1 × 18 = 19.8 days (round up to 20 days) Let the total work = 180 units Efficiency of ‘A’ = 180/18 = 10 units/day Efficiency of ‘B’ = 180/20 = 9 units/day Work completed by ‘A’ and ‘B’ in 15 days = (10 + 9) × 15 = 285 units (exceeds total units, adjust to maximum possible, which is 180 units) Since the total work is completed in the given period, x = 0 days
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