‘A’ can complete a work in 12 days and is 33.33% more efficient than ‘B’. ‘A’ and ‘B’ start the work together, but ‘A’ leaves after 6 days. The remaining work is completed by ‘B’ alone in ‘x’ days. Find the value of ‘x’.
ATQ, Time taken by ‘B’ to complete the work = 1.333 × 12 = 16 days Let the total work = 160 units Efficiency of ‘A’ = 160/12 = 13.33 units/day (round to 13 units/day) Efficiency of ‘B’ = 160/16 = 10
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