Question
16 men can complete a work in 10 days. 10 men started
the same work and left after working for βyβ days. The remaining work is completed by 6 men in 15 days. Find the value of βyβ.Solution
ATQ, Total work = 16 Γ 10 = 160 man-days. When 10 men work for βyβ days, the work done = 10y man-days. Remaining work = 160 - 10y man-days. 6 men complete the remaining work in 15 days, so: 6 Γ 15 = 90 man-days. Therefore, 10y + 90 = 160 10y = 70 y = 70/10 y = 7
More Time and work Questions
What will come in the place of question mark (?) in the given expression?
75% of (β64 Γ 8 - 16) Γ ? = 15Β²
(8.6 Γ 8.6 + 4.8 Γ 4.8 + 17.2 Γ 4.8) Γ· (8.62 β 4.82 ) = ? Γ· 19
6 0 - 20 [8 + 12 {8-8 (20-12)+20}-40] ÷ 16 =?
- What will come in place of the question mark (?) in the following questions?
144Γ·12+18Γ2=? 75% of 65% of 7/5 of 2420 = ?
Find the simplified value of the given expression:
1.82Β + 2.42Β + 1.52Β - 1.8 x 2.4 - 2.4 x 1.5 - 1.8 x 1.5
(β 196 x β 36 x β 100) = ?% of 200
72% of 486 β 64% of 261 = ?
35% of 240 β 6 2 = ? 2 β β256
