Question
A can finish a work in 25 days and B can complete the
same work in 10 days. B worked for 5 days and left the job. In how many days can A alone finish the remaining work?Solution
A can finish a work=25 days. B can complete the same work=10days. LCM of 25 and 10 =50 Let the total work =50 units Efficiency of A =50/25=2 units Efficiency of B =50/10=5 units B worked for 5 days =5×5=25 units. Remaining work =50-25 =25. Remaining work done by A =25/2 =12.5 days.
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The sum of two numbers is 25 and their difference is 15. The ratio of the numbers is:
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