"Amit" and "Bhanu" have respective completion times of 20 and 30 days for a task. They began working together on the project, but after a few days, "Amit" left and "Chintu," who can finish the entire task on her own in ten days, joined. Four days before the job was finished, "Chintu" left. Determine the amount of work completed by "Bhanu" if "Amit" and "Chintu" worked for a similar number of days.
ATQ, Let the total work = 60 units (L.C.M of 20, 30 and 10) Therefore, efficiency of ‘Amit’ = 60/20 = 3 units/day Efficiency of ‘Bhanu’ = 60/30 = 2 units/day Efficiency of ‘Chintu’ = 60/10 = 6 units/day Let ‘Amit’ and ‘Chintu’ worked for ‘d’ days According to the question, 5d + 8d + 4 × 2 = 60 13d = 52 Or, d = 4 Therefore, work will get completed in d + d + 4 = 12 days Therefore, work done by ‘Bhanu’ = 12 × 2 = 24 units Required ratio = 24/60 = 2/5
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If 12 # 34 = 14 and 67 # 88 = 106, then 45 # 67 = ?
Select the option that is related to the third number in the same way as the second number is related to the first number.
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Select the related number from the given alternatives:
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If N = 28, NET = 78, then ‘NEAT’ will be equal to?
DIMA : NSWK ∷ BJGT : (?)
