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ATQ, Let the total work be 90 units (LCM of 18 and 30) So, efficiency of 'C' = (90/18) = 5 units/day And efficiency of 'D' = (90/30) = 3 units/day New efficiency of 'C' = 60% of 5 = (0.6) X 5 = 3 units/day New efficiency of 'D' = 50% of 3 = (0.5) X 3 = 1.5 units/day So, required time =(90/(3+1.5) = 90/4.5 = 20 days
Select an appropriate figure from the four options that will come in the place of question mark (?) and complete the figure.
Which figure should replace the question mark (?) if the series were to continue?
In each of the following questions, find out which of the answer figures can be formed from the pieces given in the problem figure.
Select an appropriate figure from the four options that would complete the figure.