P, Q, R and S can do a piece of work in 20 days. If P and Q together can do it in 50 days, and R alone in 60 days, then in how many days can S alone do it?
Let, total work = LCM of (20, 50, and 60) = 300 Hence, Efficiency of (P + Q + R + S) = 15 Efficiency of (P + Q) = 6 Efficiency of R = 5 Efficiency of S = 15-6-5=4 S alone can complete the whole work in = 300/4 = 75 days.
16 × 14 + 30 × 21 = 14 × ?
(64/25)?× (125/512)?-1= 5/8
4567.89 - 567.89 - 678.89 = ?
48 ÷ 6 × √25 + 13 × 8 = ?
10 × 100 ÷ 5 + 9 = ?
3% of 842 ÷ 2% of 421 = ?
1000÷ 250 = ( 3√? × √1444) ÷ ( 3√512 × √361)
72 + 122 - 25% of 600 = ?
(13)2 - 3127 ÷ 59 = ? x 4
9999² + 1111² =?
