Question
P, Q, R and S can do a piece of work in 20 days. If P
and Q together can do it in 50 days, and R alone in 60 days, then in how many days can S alone do it?Solution
Let, total work = LCM of (20, 50, and 60) = 300 Hence, Efficiency of (P + Q + R + S) = 15 Efficiency of (P + Q) = 6 Efficiency of R = 5 Efficiency of S = 15-6-5=4 S alone can complete the whole work in = 300/4 = 75 days.
The value of ((0.27)2-(0.13)2) / (0.27 + 0.13) is:
4.56 + 56.4 + 64.5 = ? + 10.46
(3/7) x 868 + 25% of 240 = (? + 65)
(506 ÷ 22 + 9 × 3) × ? = 900 ÷ 9
(72 + 30) ÷ 6 + [{75 ÷ 25) + 6} × 2] = ?
(560 ÷ 32) × (720 ÷ 48) = ?
√729 × 5 + 270 - 3 ÷ ∛27 + 4 × ? = 484
(392 + 427 + 226 – 325) ÷ (441 + 128 – 425) = ?Â
212.3 × 4414.7 × 4623.4 × 4845.85 = 462?
‘A’ and ‘B’ invested Rs. 5000 and Rs. 4200, respectively in a business, together. After 7 months, ‘A’ withdrew 25% of his initial investment...