Question
‘R’ and ‘S’ can complete an assignment in 72
days and 90 days respectively while ‘R’, ‘S’ and ‘T’ together can complete the same assignment in 24 days. Find the time taken by ‘T’ alone to complete 30% of the work.Solution
ATQ Let total amount of work = 360 units (LCM of 72 and 90) Amount of work done by ‘R’ in one day = 360/72 = 5 units Amount of work done by ‘S’ in one day = 360/90 = 4 units Amount of work done by ‘R’, ‘S’ and ‘T’ in one day = 360/24 = 15 units Amount of work done by ‘T’ in one day = 15 – 5 – 4 = 6 units Desired time = (0.30 × 360)/6 = 18 days
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