A and B can complete a job together in 30 days; B and C can complete the same job together in 25 days, while C and A can complete the same job together in 10 days. In how many days will A, B, and C be able to complete the same job alongside D, who is only 75% as efficient as C?
A+B= 30 B+C=25 C+A=10days LCM of 30, 25, and 10 = 150 A+B    B+C     C+A 30       25       10           150  5         6       15 Total 2(A+B+C) = 5+6+15+=26 A+B+C =13 C = 13-5 =8 D= 8×75/100 =6 NOW A+B+C+D = 13+6=19 SO total days = 150/19 =7(17/19) days
Simplify the following expression:
  (525 +175) ² - (525 – 175) ² / (525 × 175)
(1/2) – (3/5) + 3(1/3) = ? + (5/6)
48 ÷ 6 × √25 + 13 × 8 = ?
1.25 × 36 + 2.75 × 40 = ? × 3.1
1 + 1 + 1/2+ 1/3 + 1/6 + 1/4 is equal to ____
1500 × 60% of 25% = ? 2Â
Find the HCF of 15x2 + 8x – 12, 3x² + x – 2, 3x² - 2x, 9x² - 12x + 4
(〖(0.5)〗^(1/3) × 〖(1/125)〗^(1/4) × 〖25〗^(1/6) ×〖(6.25)〗^(2/3))/(〖(2.5)〗^(2/3) × 5^(-1/2) × 〖(1/5)〗^(-2)×〖3125ã...
If x - 1/x = 9, then the value of x² + 1/ x² is:
3(2/3) of 2(5/11) of 5(2/5) of 75 = ?
