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A+B= 30 B+C=25 C+A=10days LCM of 30, 25, and 10 = 150 A+B B+C C+A 30 25 10 150 5 6 15 Total 2(A+B+C) = 5+6+15+=26 A+B+C =13 C = 13-5 =8 D= 8×75/100 =6 NOW A+B+C+D = 13+6=19 SO total days = 150/19 =7(17/19) days
The truth table for a NOR gate has an output of 0 when:
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The process of finding hidden structure in unlabeled data is called
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