8 men working 6 hours a day can complete a piece of work in 6 days. If efficiency of each woman is 20% more than that of each man, then how many women working 4 hours a day are needed to complete the work in 12 days?
Let the efficiency of each man be 'M' units/day. Let number of women required to complete the work in 12 days be 'N'. So, efficiency of each woman = '1.2M' units/day ATQ: We have, 8 X M X 6 X 6 = N X 1.2M X 4 X 12 Or, 288 = N X 57.6 So, 'N' = (288/57.6) = 5
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