'A' can complete a project in 15 days but worked only the first 4 days. 'B', who is 80% as efficient as 'A', takes over. How long does 'B' need to finish the remaining work?
Let the efficiency of 'A' be 'x' units/day So, efficiency of 'B' = '0.8x' units/day Total work = x X 15 = '15x' units Work done by 'A' in 4 days = 4 X x = '4x' units So, remaining work = 15x - 4x = '11x' units So, time taken by 'B' to finish the remaining work = (11x ÷ 0.8x) = 13(3/4) days
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