Let the efficiency of 'A' be 'x' units/day So, efficiency of 'B' = '0.8x' units/day Total work = x X 15 = '15x' units Work done by 'A' in 4 days = 4 X x = '4x' units So, remaining work = 15x - 4x = '11x' units So, time taken by 'B' to finish the remaining work = (11x ÷ 0.8x) = 13(3/4) days
There are 3 series, you have to find value of a, b, c and then establish relation among a,b,c.
19, 25, 45, a, 553, 2767
1560 760 360 160 6...
35 36 40 49 65 ?
...22 15 10 20 33 93.5
...299, 302, 308, 317, ?, 344
7, 8, 12, 21, 37, ?
1335 737 355 141 47 ?
...? + (55)2= (140)2– (80)2– 6278
148, ‘?’ , 15 4 , 17 8 , 23 8 , 35 8 , 56 8
94 282 284 852 856 2562
...123 125 129 132 ? 145