'A' alone can finish a job in 12 days. If 'A' is twice as efficient as 'B' who is 20% as efficient as 'C', then find the time taken to finish the job if they all work together.
Let the total work be '24x' units. Efficiency of 'A' = (24x/12) = '2x' units/day Efficiency of 'B' = (2x X 0.5) = 'x' unit/day Efficiency of 'C' = (x ÷ 0.2) = '5x' units/day Time taken to finish the work when all 'A', 'B' and 'C' work together = {24x/(2x + x + 5x)} = 3 days
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