Question
Arjun, Bharat and Chintu together can complete a task in
8 days. Bharat is 25% less efficient than Arjun. Arjun and Chintu together can complete the task in 12 days. In how many days Chintu alone can complete the task?Solution
ATQ, Let the total work = 24 units (LCM of 8 and 12) Amount of task completed by Arjun, Bharat and Chintu together in one day = 24/8 = 3 units Amount of task completed by Arjun and Chintu together in one day = 24/12 = 2 units Amount of task completed by Bharat alone in one day = 3 – 2 = 1 unit Amount of task completed by Arjun alone in one day = 1/0.75 = 4/3 units Amount of task completed by Chintu alone in one day = 2 – 4/3 = 2/3 units Time taken by Chintu alone to complete the task = 24/(2/3) = 36 days
√ [? x 11 + (√ 1296)] = 16
? = 6.25% of 240 + 252 + 172 – 16 × 17
436 × 794 – 68210 =? + 85730
?/4 ÷ 9/? = 15% of 800 + `1(2/3)` × `1(1/5)` × 1/2
16 × 14 + 30 × 21 = 14 × ?
60% of 250 + 14 × 10 - 210 = ?
What will come in the place of question mark (?) in the given expression?
30% of 520 + 16% of 1500 = ? + 244
33 × 5 - ?% of 250 = 62 - 6
140% of 9/8 of ? = 108% of 2800
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