Question
"Akash and Bittu can individually
complete a task in 40 days and 50 days, respectively. They start working together, and after 10 days, Chinky joins them. The work is finished in a total of 20 days. How many days would Chinky take to complete the same task alone?"Solution
ATQ, Part of the task done by Akash and Bittu in one day = (1/40) + (1/50) = 9/200 Part of the task done by Akash and Bittu in 10 days = 90/200 Remaining work = 1 ā (90/200) = 110/200 Let the time taken by Chinky alone to complete the work be ādā days. So, (90/200) + (10/d) = 110/200 10/d = (110/200) ā (90/200) d = 100 So, time taken by Chinky alone to complete the task = 100 days
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