Question
"Akash and Bittu can individually
complete a task in 40 days and 50 days, respectively. They start working together, and after 10 days, Chinky joins them. The work is finished in a total of 20 days. How many days would Chinky take to complete the same task alone?"Solution
ATQ, Part of the task done by Akash and Bittu in one day = (1/40) + (1/50) = 9/200 Part of the task done by Akash and Bittu in 10 days = 90/200 Remaining work = 1 – (90/200) = 110/200 Let the time taken by Chinky alone to complete the work be ‘d’ days. So, (90/200) + (10/d) = 110/200 10/d = (110/200) – (90/200) d = 100 So, time taken by Chinky alone to complete the task = 100 days
Four terms are in proportion. The first, second and fourth terms are 4, 22, and 33. Find the third term.
4Â Â Â Â Â Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â Â Â Â Â Â 24Â Â Â Â Â Â Â Â Â Â Â 91Â Â Â Â Â Â Â Â Â Â Â 462Â Â Â Â Â Â Â Â Â 2763
18Â Â Â ...
A series is 11, 20, 42, 82, 166, 330
If another series 4, a, b, c, d, 106 follows the same pattern as the given number series, then find the appr...
12, 24, 72, 288, 1440, ?
60  61  126  387  ?   7845
315 146 267 ? 235 210
Three series are given below. You have to find the values of P, Q and R, then establish a relationship among them.
I:Â Â 840, P , 584, 456, 5...
28 34 63 ? 769 3847
...105   107   111   114   ?   127
4 5.5 19 .5 98.5 694 6251.5
...
