A and B can each finish a task in 32 days and 36 days respectively. They begin the task together, but after 12 days, A leaves. How long will it take for B to complete the remaining work alone?
Let total amount of work = 288 units (LCM of 32 and 36) Amount of work done by A in one day = 288/32 = 9 units Amount of work done by B in one day = 288/36 = 8 units Amount of work done by A and B together in 12 days = 12 × 17 = 204 units Remaining work = 288 – 204 = 84 units Desired time = 84/8 = 10.5 days Hence, option c.
(7/4×18/21)+ (51/7× 28/17) + (25/2 × 48/10) =?
60% of 250 + 14 × 10 - 210 = ?
140% of 1270 + 60% of 2085 = 1881 + ‘?’% of 287
2856 ÷ 34 = ?% of 240
154 × 7 + 480 × 5 =?% of 6956
17.5% of 400 – 24% of 150 = ?
72% of 400 – 23% of 1020 = 120% of ?
666(2/3)% of 30 - 116(2/3)% of 90 =?
I. 8x² - 74x + 165 = 0
II. 15y² - 38y + 24 = 0
12% of 450 + 16% of 1500 = ?
