Question

    A is capable of finishing a task in 60 days. B requires

    40% more time than A to finish the same task. How many days will A and B need to complete 80% of the work together?
    A 24 days Correct Answer Incorrect Answer
    B 28 days Correct Answer Incorrect Answer
    C 32 days Correct Answer Incorrect Answer
    D 30 days Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Time taken by B to complete the whole work = 1.40 × 60 = 84 days Let total work = 420 units (LCM of 60 and 84) Efficiency of A = 420/60 = 7 units per day Efficiency of B = 420/84 = 5 units per day Desired time = (0.80 × 420)/12 = 28 days

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