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Let efficiency of ‘B’ is ‘x’ units per day Efficiency of ‘A’ = 0.60 × x = 0.6x units per day Efficiency of ‘C’ = x/1.25 = 0.8x units per day Total amount of work = (x + 0.6x + 0.8x) × 45 = 108x units Amount of work completed by ‘B’ and ‘C’ together in 40 days = 1.8x × 40 = 72x units Remaining work = 108x – 72x = 36x units Desired time = 36x/0.6x = 60 days
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