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Let the total work be 60 units. So, efficiency of 'A' = 60 ÷ 30 = 2 units/day So, efficiency of 'B' = 3 X 2 = 6 units/day And efficiency of 'C' = 6 ÷ 2 = 3 units/day Let the number of days for which 'B' worked alone be 'd'. So, (d X 6) + (11 - d) X (2 + 3) = 60 Or, 6d + 55 - 5d = 60 Or, 'd' = 5 So, 'B' worked alone for 5 days So, 'B' should've joined them after (11 - 5) = 6 days
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