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    Question

    Bijay can complete a task on his

    own in 40 days, while Ajay can finish the same task in 25 days. If they alternate working on the task starting with Bijay, in how many days will the task be completed?
    A 45 days Correct Answer Incorrect Answer
    B 36 days Correct Answer Incorrect Answer
    C 31 days Correct Answer Incorrect Answer
    D 22 days Correct Answer Incorrect Answer

    Solution

    ATQ, Let the total task be 200 units {LCM (25 and 40)} So, efficiency of 'Ajay' = 200 ÷ 25 = 8 units/day And efficiency of 'Bijay' = 200 ÷ 40 = 5 units/day Task done in every 2 days = 8 + 5 = 13 units So, task done in 30 days by 'Ajay' and 'Bijay' = (30/2) × 13 = 195 units Time taken by 'Bijay' to do the remaining work = {(200 - 195)/5} = 1 day So, total time taken = 1 + 30 = 31 days

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