Question
Six women and two men can
complete a task in 10 days. If the efficiency of a woman is twice that of a man, how many days will it take for eight women and five men to finish the same task?Solution
ATQ, Let the efficiency of each woman and each men be 'x' units/day and 'y' units/day Or, x = 2y Let the required number of days be 'd' days So, (6x + 2y) × 10 = (8x + 5y) × d Or, (12y + 2y) × 10 = (16y + 5y) × d Or, 14y × 10 = 21y × d So, d = (14y × 10)/21y = 20/3 = 6(2/3)
1120.04 – 450.18 + 319.98 ÷ 8.06 = ?
784.69 + 86.96 ÷ 29.01 = 40.01 + ? + 367.88
960.02 of 238.89 ÷ 144.01 of 79.97 = ?
√2401 × (√2116 ÷ 23) × 21 ÷ 3 = ?
80.08% of 1250.25 + 64.02% of 1200 = 24.02 × 36.025 + ?% of 2259.98
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
If the length of one side of a rhombus is 16cm then find its surface area. (use √ 3 = 1.732)
(51.99² - 19.05² )÷ ? = 14.11² - 140.33
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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