Question
Six women and two men can
complete a task in 10 days. If the efficiency of a woman is twice that of a man, how many days will it take for eight women and five men to finish the same task?Solution
ATQ, Let the efficiency of each woman and each men be 'x' units/day and 'y' units/day Or, x = 2y Let the required number of days be 'd' days So, (6x + 2y) Ă— 10 = (8x + 5y) Ă— d Or, (12y + 2y) Ă— 10 = (16y + 5y) Ă— d Or, 14y Ă— 10 = 21y Ă— d So, d = (14y Ă— 10)/21y = 20/3 = 6(2/3)
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