Let the total work = L.C.M of 35, 20 and 28 = 140 units Then, efficiency of 'A' = 140 ÷ 35 = 4 units/day Efficiency of 'B' = 140 ÷ 20 = 7 units/day Efficiency of 'C' = 140 ÷ 28 = 5 units/day Work done by 'A' alone in 5 days = 4 X 5 = 20 units So, work done by 'B' and 'C' in 'x' days = 140 - 20 = 120 units So, x = 120 ÷ (7 + 5) = 10
14 36 80 168 ? 696
Complete the series choosing the missing number.
110, 99, 86, ___, 54, 35.
47, 72, 122, ?, 297, 422
150, 158, 131, 195, 70, ?
324 972 486 1458 729 ?
...140, 146, 158, 176, ?, 230
45, 166, 607, 1568, 3249, ?
1000 100 20 ? 2.4 1.2
289 169 121 ? 25 9
...415 246 367 ? 335 310
...