Question
"A" and "B" together can complete a task in 16 days.
Additionally, "B" alone is able to complete 40% of the task in 16 days. Based on this information, calculate the time it would take for "A" to complete 60% of the task on their ownSolution
Time taken by 'B' to do 100% of the work alone = 16 Ć· 0.4 = 40 days Let total work be 80 units {LCM (40 and 16)} So, efficiency of 'B' = 80 Ć· 40 = 2 units/day And efficiency of 'A' and 'B' together = 80 Ć· 16 = 5 units/day So, efficiency of 'A' = 5 - 2 = 3 units/day So, required time = 80 X 0.6 Ć· 3 = 16 days
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