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Work done by A and B together in 4 days = 4 × (1/12 + 1/16) = 4 × (4/48 + 3/48) = 4 × 7/48 = 28/48 = 7/12 of the work. Remaining work = 1 - 7/12 = 5/12. Work done by B and C in 6 days = 6 × (1/16 + 1/C) = 5/12. Simplify: 6 × (1/16 + 1/C) = 5/12. 1/16 + 1/C = (5/12) ÷ 6 = 5/72. 1/C = 5/72 - 1/16 = 5/72 - 9/144 = (10 - 9)/144 = 1/144. C alone can complete the work in 144 days.
…………… method helps in maintaining high genetic variability in a population due to repeated intermating of heterozygous plants/populations.
...Principle hydrogen producing bacteria is
______________ is a form of asexual reproduction in plants where seeds are produced without the involvement of meiosis or fertilization. In this process...
During anaphase, the significance of sister chromatids separating and moving towards opposite poles is?
In DNA fingerprinting large quantity of DNA (5-10 mg) is required and markers are ………………………
Which method is primarily used for genetic improvement in highly heterozygous, asexually propagated species like sugarcane and potato?
During which phase of mitosis do chromosomes align along the equatorial plane of the cell?
The term that describes a gene's ability to produce different degrees of the same trait?
In the pedigree method, individual plants are selected from …………….. and subsequent generations, and their ...
Flowers do not open at all which ensures complete self pollination in
