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ATQ,
Let the total task = 120 units (LCM of 20, 24 and 30) Amount of task done by P alone in one day = 120/20 = 6 units Amount of task done by Q alone in one day = 120/24 = 5 units Amount of task done by R alone in one day = 120/30 = 4 units Amount of task done by all of them together in 4 days = 4 × (6 + 5 + 4) = 60 units Amount of task done by Q alone in 3 days = 3 × 5 = 15 units Amount of task done by Q and R together in middle = 120 – 60 – 15 = 45 units Time taken by Q and R together to complete 45 units task = 45/ (5 + 4) = 45/9 = 5 units So total time taken to complete the task = 5 + 4 + 3 = 12 days
I). p2 + 22p + 72 = 0,
II). q2 - 24q + 128 = 0
I. 35x² - 24x – 35 = 0
II. 72y² - 145y + 72 = 0
A and B are the roots of equation x2 - 13x + k = 0. If A - B = 5, what is the value of k?
If x2 - 3x - 18 = 0 and y2 + 9y + 18 = 0, which of the following is true?
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 29x² - 177x + 270 = 0
Equation 2: 31y² - 152y + ...
I. 8/(21x) - 2/7 = 0
II. 16y² - 24y +9 = 0
I. 2x² + 11 x + 15 = 0
II. 2y² - 19 y + 44 = 0
I. 3x2 - 14x + 15 = 0
II. 15y2- 34 y + 15 = 0
I. 2p2 - 3p – 2 = 0 II. 2q2 - 11q + 15 = 0
I. 3p2 - 11p + 10 = 0
II. 42q2 + q -1 = 0