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ATQ,
Let the total task = 120 units (LCM of 20, 24 and 30) Amount of task done by P alone in one day = 120/20 = 6 units Amount of task done by Q alone in one day = 120/24 = 5 units Amount of task done by R alone in one day = 120/30 = 4 units Amount of task done by all of them together in 4 days = 4 × (6 + 5 + 4) = 60 units Amount of task done by Q alone in 3 days = 3 × 5 = 15 units Amount of task done by Q and R together in middle = 120 – 60 – 15 = 45 units Time taken by Q and R together to complete 45 units task = 45/ (5 + 4) = 45/9 = 5 units So total time taken to complete the task = 5 + 4 + 3 = 12 days
2048 × 1824 ÷ 76 = (? - 212) × 64
22 + 60 × 3 ÷ 12 = ?
17% of 250 + ? = 108
(5/8 of 480 - 30% of 420)² ÷ (√81 + 25% of 320) = ?
(1296 ÷ 54 × 24 + 24) = ? × 150
(18 2 – 17 2) x (1/5) + ? = 148
Find the value of the given expression.
[76 – {90 ÷ 5 × (24 – 36 ÷ 3) ÷ 3}]
∛857375 + ∛91125 = ? + √6889
20 × 224÷ 16 – 50 = ? + 100
...2850 ÷ 2.5 - ? × 42 = 300