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Let the total work = L.C.M of 24 and 14 = 168 units So, efficiency of ‘Akash’ alone = 168 ÷ 24 = 7 units/day Combined efficiency of ‘Akash’ and ‘B’ = 168 ÷ 14 = 12 units/day So, efficiency of ‘Bittu’ alone = 12 – 7 = 5 units/day Work completed by ‘Bittu’ alone in 19.6 days = 19.6 × 5 = 98 units Time taken by ‘Akash’ alone to complete the remaining work = (168 – 98) ÷ 7 = 10 day
If in a certain code language
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3....
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Frog : Amphibian :: Whale...
