ATQ,
Let the total work = L.C.M of 24 and 14 = 168 units So, efficiency of ‘Akash’ alone = 168 ÷ 24 = 7 units/day Combined efficiency of ‘Akash’ and ‘B’ = 168 ÷ 14 = 12 units/day So, efficiency of ‘Bittu’ alone = 12 – 7 = 5 units/day Work completed by ‘Bittu’ alone in 19.6 days = 19.6 × 5 = 98 units Time taken by ‘Akash’ alone to complete the remaining work = (168 – 98) ÷ 7 = 10 day
25, 200, 40, ?, 64, 512
108 329 ? 2975 8928 26789 .
35 70 105 140 175 ?
48 83 118 153 188 ?
If 14, 32, x, 50, -13, 86,
then, find the value of (10x + 5x – 20)?
...30 15 15 30 120 ?
...6 6 13 39 ? 226
...To find the Next number in the given series.
0 6 24 60 120 ?
...60 61 126 387 ? 7845
9 15 90 95 475 479
6 a b c d e
Find the value of c.
...
