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ATQ,
Time taken by 'Bhavna' to complete the work = 28 + 7 = 35 days Let the total work be 140 units (LCM of 28 and 35) Efficiency of 'Pawan' = (140/28) = 5 units/day Efficiency of 'Bhavna' = (140/35) = 4 units/day Work completed by 'Pawan' and 'Bhavna' in 10 days = (5 + 4) × 10 = 90 units Remaining work = 140 - 90 = 50 units So, efficiency of 'Raja' = 50/5 = 10 units/day Therefore, time taken by 'C' to complete the entire work = 140/10 = 14 days
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