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ATQ, Let total work be 15 units {LCM of 5 and 15} Efficiency of ‘Pawan’ = (15/5) = 3 units/hour Eiciency of ‘Qureshi’ = (15/15) = 1 units/hour Work done by ‘Pawan’ and ‘Qureshi’ in every 2 hours = (3 + 1) = 4 units So, work done in irst 6 hours = 4 × 3 = 12 units Remaining work = (15 – 12) = 3 units Since, ‘Pawan’ is next in line to do the work, he will finish the remaining work in (3/3) = 1 hour So, total time taken by ‘Pawan’ and ‘Qureshi’ to do the work together = 1 + 6 = 7 hours Therefore, the work will be inished at 4:00 p.m. i.e., 7 hours after ‘Pawan’ started working.
If A = (7)1/3 + (7) -1/3, then the value of {3A3 – 9A} will be:
√4096 + √(?) + 13 – 29 = 148
if a2 + b2 + c2 = 2(4a -5b -9c)-122 , then a-b-c = ?
If, 4x2 + y2 + 12x + 6y + 18 = 0, then find the value of (2x + y)/(y + 6x).
If a + b = 56 and (a – b)² = 496, find the value of the product of a and b.
The speed of a car is 25% more than that of a bike. Both of them start from a same point. After travelling for 4 hours, the speed of the bike is increas...
√(92×8 ×52+700) = ?