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ATQ,
Let the total task = L.C.M of 60 and 28 = 420 units Then, efficiency of ‘Bittu’ alone = 420 ÷ 60 = 7 units/day Combined efficiency of ‘Anoop’ and ‘Bittu’ = 420 ÷ 28 = 15 units/day So, efficiency of ‘Anoop’ alone = 15 – 7 = 8 units/day task done by ‘Anoop’ alone in 35 days = 8 × 35 = 280 units Remaining task = 420 – 280 = 140 units So, time taken by ‘Bittu’ alone to complete the remaining task = 140 ÷ 7 = 20 days.
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