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Let the total work be LCM of 12, 15, and 8 = 120 units. Work done per day by A and B = 120 / 12 = 10 units Work done per day by B and C = 120 / 15 = 8 units Work done per day by A, B, and C = 120 / 8 = 15 units Work done per day by A and C = (A, B, C) - (B) = 15 - 8 = 7 units Time taken by A and C = Total Work / Work per Day = 120 / 7 Correct answer: d.
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