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Let the total work be 70 units (LCM of 14, 10 and 35) Efficiency of 'Tarun' and 'Saurabh' = (70/10) = 7 units/day Efficiency of 'Tarun' and 'Reena' = (70/14) = 5 units/day Efficiency of 'Reena' and 'Saurabh' = {70 ÷ (35/3) } = 6 units/day Efficiency of 'Tarun', 'Reena' and 'Saurabh' = (7 + 5 + 6) ÷ 2 = 9 units/day Efficiency of 'Tarun' = 9 - 6 = 3 units/day Efficiency of 'Saurabh' = 9 - 5 = 4 units/day Therefore, required time = (70/3) - (70/4) = (35/6) days
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