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Total work = LCM of 12 and 20 = 60 units. Efficiency of A = 60 ÷ 20 = 3 units/day. Efficiency of A and B together = 60 ÷ 12 = 5 units/day. Work done by A in 5 days = 5 × 3 = 15 units. Remaining work = 60 - 15 = 45 units. Time taken by A and B together to complete remaining work = 45 ÷ 5 = 9 days. Correct Option: d) 9 days
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