A contractor undertook to make 20 km of roadway in 48 weeks. In 28 weeks, 8 km was completed by 120 men working 12 hours a day. The men then agreed to work 3 hour a day overtime and some women were engaged to assist them, the work was finished in the stipulated time. How many women were employed, if the work of 8 men is equal to that of 5 women.
8M = 5W So M/W = 5/8 By M1D1H1/W1 = M2D2H2/W2 (120M × 12 × 28)/8 = [(120M + xW) × 15 × 20]/12 (120×5 × 12 × 28)/8 = [(120×5 + x×8) × 15 × 20]/12 28×3×12 = 600 +8x 8x = 1008 - 600 = 408 So x = 408/8 = 51
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