Question
Two pipes A and B can fill a tank in 24 min., and 32
min, respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 minutes?Solution
Let B be closed after x minutes. Then, Part filled by (A+B) in x min. + part filled by A in (18 – x) min. = 1 x (1/24  +  1/32) + (18 – x )  × 1/24  = 1 ⟹  7x/96  +  (18-x)/24   = 1 ⟹7 x + 4 (18 – x) = 96 ∴ x = 8 ∴ Hence, B must be closed after 8 minutes. Alternate Solution: A        B 24       32 LCM = 96 4   :     3 B is closed in between hence A filled for whole all time so A filled in 18 hrs = 18 
4 = 72 units So rest work (96-72=24) is done by B in = 24/3 = 8 min hence B is closed by 8 min
Select the most appropriate opposite of the given COMPLIMENTATY
Select the most appropriate ANTONYM of the bold word.
The politician was flummoxed by the questions put to him.
Speaking or performing without preparation
Select the word with the correct spelling.
The manager was cautious in making decisions.
A child born after his or her father’s death
Swindle
anxiety
Select the wrongly spelt word.
A large building where aircraft are stored.
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