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Let’s assume that pipe B alone can the tank in x minutes, so pipe B fills 1/xth part of tank in one minute. Pipe A can fill the tank 5 times faster than pipe B, so pipe A fills 5/xth part of tank in one minute. Together, the two pipes fill the tank in 50 minutes, so together they fill 1/50th part in one minute. => 1/x + 5/x = 1/50 ⇒ 6/x = 1/50 ⇒ x = 300 minutes ∴ Pipe B alone fills the tank in 300 minutes.
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