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Let the total work = 120 units Efficiency of A when he can complete the whole work in 30 hours = 120/30 = 4 units/hour Efficiency of A when he can complete the whole work in 24 hours = 120/24 = 5 units/hour Amount of work done in 10 hours = 10 × 4 = 40 units Time taken to complete the remaining work = (120 – 40)/5 = 16 hours Therefore, total time taken = 16 + 10 = 26 hours
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