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Let the total work be = 1 One day work done by Harish and Bimal = 1/20 Work done by Harish and Bimal in 15 days = 1/20 × 15 = 3/4 ⇒ Remaining work = 1 - 3/4 = 1/4 Harish did remaining work in 10 days alone. ⇒ One day work done by Harish = 1/4 ×1/10 = 1/40 ∴ Time taken by Harish to do the entire task alone = 1 ×40 = 40 days
I. 2y2+ 13y + 15 = 0
II. 2x2+ 11 x + 12 = 0
Equation 1: 2x2 - 21x + 54 = 0
Equation 2: 4y2 - 23y + 15 = 0
Difference between the roots of equation 1 is approx...
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 30x + 221 = 0
Equation 2: y² - 28y + 189 = 0
I. 4p² + 17p + 15 = 0
II. 3q² + 19q + 28 = 0
I. 3x2 = 2x2 + 9x – 20
II. 3y2 = 75
Solve the given two equations and answer the two questions that follow as per the instructions given below.
I. (1/4) + 7.5p(-2) = 3.62...
If a and b are the roots of x² + x – 2 = 0, then the quadratic equation in x whose roots are 1/a + 1/b and ab is
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
1.3wx = 40 – wy
2. b2 = 2b + p
3. d2 + d = q
Now, observe the given conditions:
One root of equation...
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 40x + 375 = 0
Equation 2: y² - 36y + 324 = 0