Pipes A and B can fill an empty tank in 6 and 8 hours respectively, while pipe C can empty the full tank in 10 hours. If all three pipes are opened together, then the tank will get filled in:
Pipe A (+)        pipe B (+)         pipe C (-) 6                     8                     10                        120 (LCM of 6,8,10)-total 20                   15                   12.      (efficiency) Tank fill in 1 hour =20+15-12=23unit. In 5 hours =23×5=115 unit Remaining empty tank. =120-115=5. 5 units fill in the tank in 5/23 hours. Total hours =5+5/23=5(5/23).
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