The diameters of three inlet pipes of a cistern are 1.5 cm, 2 cm and 2.5 cm respectively. The pipe with the maximum diameter can alone fill up the cistern in 3 hours and 36 minutes. Find the time in which the empty cistern will be filled if all the three inlet pipes are opened together.
Diameters of three inlet pipes of a cistern = 1.5 : 2 : 2.5 = 3:4:5 Ratio of efficiency will be = Square of diameter => 9 : 16 : 25 Total work = Time x Maximum diameter efficiency = 216 min x 25 If all three work = (216 x 25)/50(9+16+25) = 108 min = 1 hour 48 min
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