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P, Q and R can do a piece of work in 10, 20 and 30 days respectively. Total work = 60 (LCM of 10, 20 and 30) P's efficiency = 60/10 = 6 Q's efficiency = 60/20 = 3 R's efficiency = 60/30 = 2 Pattern of work = PQ, PR, PQ, PR... Work done by PQ and PR in 2 days = (6 + 3) + (6 + 2) = 17 2 days => 17 units 2 × 3 = 6 days => 17 × 3 = 51 units remaining 9 units done by PQ in = work/efficiency = 9/(6 + 3) = 1 day Total time taken = 6 + 1 = 7 days ∴ P, Q and R complete the work together when P is assisted by Q and R on every alternate day in 7 days.
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Select the figure that will come next in the following series.
Question Figure:
Select the option figure which is embedded in the given figure as its part (rotation is NOT allowed).
Select the combination of letters that when sequentially placed in the blanks of the given series will complete the series.
TUP _ _ _PKT _ _ KTUP_
Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which letter...
Select the figure that will replace the question mark (?) in the following figure series.
Select the set in which the numbers are related in the same way as are the numbers of the following sets.
(NOTE : Operations should be performed ...
