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Total Distance = 90km Total Time = 15 hours 4/5th of the time = 15 × 4/5 = 12 hours Now, remaining distance = 90-45 = 45km Remaining time = 15 – 12 = 3 hours Average speed to cover the distance of 45 km will be 45/3 = 15km/hr.
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If sin 2A = cos (3A - 60o) , then find the value of sec 2A.
What is the value of (4/3) cot2 (p/6) + 3 cos2 (150o) – 4 cosec2 45o + 8 sin (p/2)?
...If 2x = cosec @ and 4/x = cot @ then the value of 2(x ² - 1/x ² ) is
If sin A = (4/5), then find the value of {cosec A × cos A + sec A × tan A}.
If tan θ = 4/3 and θ is an acute angle, find the value of sin θ + cos θ.
A man observes the top of a tower at an angle of elevation of 30°. He walks 100 meters closer to the tower, and the angle of elevation becomes 60°. If...
(tan 5x - tan 3x - tan 2x) = ?
