Question
Two trains are running on parallel lines in the same
direction at the speed of 75 km/h and 39 km/h respectively. The faster train crosses a man in the slower train in 56 second. If the length of the slower train is 4/7th of the faster train, then find the length of the slower train.Solution
According to the question, => (75 – 39) × (5/18) = D/56 => D = 560 m Length of the faster train = 560 m Length of the slower train = 560 × (4/7) = 350 m
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