Question
Train ‘A’ running with a speed of 126 km/hr
crosses a vertical pole in 20 seconds. Find the approx. time taken by the train ‘A’ to cross a train ‘B’ whose length is 10 metres less than that of train ‘A’ and whose speed is 1/5 more than that of train ‘A’ if both are running in opposite direction.Solution
Speed of train ‘A’ = 126 × (5/18) = 35 m/sec
Length of train ‘A’ = 35 × 20 = 700 metres
Length of train ‘B’ = 700 – 10 = 690 metres
Speed of train ‘B’ = 35 + (35/5) = 42 m/sec
Required time taken = (700 + 690)/(35 + 42) = 18.05 = 18 seconds
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