Question
Train ‘A’ running with a speed of 108 km/hr crosses
a vertical pole in 12 seconds. Find the approx. time taken by the train ‘A’ to cross a train ‘B’ whose length is 140 metres less than that of train ‘A’ and whose speed is 1/4 more than that of train ‘A’ if both are running in opposite direction.Solution
Speed of train ‘A’ = 108 × (5/18) = 30 m/sec Length of train ‘A’ = 30 × 12 = 360 metres Length of train ‘B’ = 360 – 140 = 220 metres Speed of train ‘B’ = 30 + (30/4) = 37.5 m/sec Required time taken = (360 + 220)/(30 + 37.5) = 8.59 = 9 seconds
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