Question
Train βAβ running with a speed of 108 km/hr crosses
a vertical pole in 12 seconds. Find the approx. time taken by the train βAβ to cross a train βBβ whose length is 140 metres less than that of train βAβ and whose speed is 1/4 more than that of train βAβ if both are running in opposite direction.Solution
Speed of train βAβ = 108 Γ (5/18) = 30 m/sec Length of train βAβ = 30 Γ 12 = 360 metres Length of train βBβ = 360 β 140 = 220 metres Speed of train βBβ = 30 + (30/4) = 37.5 m/sec Required time taken = (360 + 220)/(30 + 37.5) = 8.59 = 9 seconds
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