A train has to cover a distance of 112 km in 14 hours. If it covers half journey in 3/5th time, then the speed of covering the remaining distance in the time left has to be:
Speed = Distance/time = 112/14 = 8 km/hr According to the question, New time = 3/5 x 14 = 8.4 hrs New distance = 1/2 x 112 = 56 km Required speed = Distance left/Time left = 56/5.6 = 10 km/hr
Value of (x7/x6)6/5 is:
if 3P=9q=27t and 1/3P+1/6q+1/9t=36/7 , then t = ?
(0.36)-1.5= ?
(5⁴) 5 × (25³)³ = ?
Which among the following is the greatest?
296, 372, 460, 548
What is the value of x?
0.064 x 0.47 = 0.4x x (0.0256)2
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...Find the Value of √(-√3+√(3+8√(7+4√3)))?
If 2x = 3y = 6-z, then (1/x) + (1/y) + (1/z) =?
Find the value of 56× 59÷ 514= ?
