A 160 m long train crosses another 290 m long train running in the opposite direction in 10 seconds. If the shorter train crosses a pole in 8 seconds, what is the speed of longer train?
Speed of the shorter train = 160/8 = 20 m/sec Let the speed of the longer train be x km/hr According to the question, ⇒ (20 + x) = (160 + 290)/10 ⇒ 20 + x = 450/10 ⇒ x = 45 – 20 = 25 ⇒ x = 25 x 18/5 = 90 km/hr
I. x2 – 10x + 21 = 0
II. y2 + 11y + 28 = 0
I. 2y² - 35y + 132 = 0
II. 2x² - 31x + 110 = 0
I. 24x² - 58x + 23 = 0
II. 20y² + 24y – 65 = 0
I. √(74x-250 )– x=15
II. √(3y²-37y+18)+ 2y=18
I. 2y2- 37y + 143 = 0
II. 2x2+ 15x – 143 = 0
I. 2x2 + 12x + 18 = 0
II. 3y2 + 13y + 12 = 0
I. x2 + 16x + 63 = 0
II. y2 + 2y - 15 = 0
A and B are the roots of equation x2 - 13x + k = 0. If A - B = 5, what is the value of k?
I. (x13/5 ÷7) = 5488 ÷ x7/5
II. (y2/3 × y2/3 ) ÷ √4 = (343y)1/3...
I. 117x² + 250x + 117 = 0
II. 54y² -123y + 65 = 0
