Train P travelling at 52 km/hr crosses another train Q, having three fourth of its length and travelling in opposite direction at 20 km/hr in 21 seconds. Train P passed a railway platform in 36 seconds. Find the length of platform.
Let the length of the first train is x metre Length of second train = 3x/4 Therefore, (52 + 20) x 5/18 = {x + (3x/4)}/21 ⇒ 72 x 5/18 = (7x/4)/21 ⇒ x = 240 m Therefore, let the length of the platform be y metre ⇒ 52 x 5/18 = (240 + y)/36 ⇒ 520 = 240 + y ⇒ y = 520 – 240 = 280 m
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