Train P travelling at 60 km/hr crosses another train Q, having three fourth of its length and travelling in opposite direction at 30 km/hr in 28 seconds. Train P passed a railway platform in 36 seconds. Find the length of platform.
Let the length of the first train is x metre Length of second train = 3x/4 Therefore, (60 + 30) x 5/18 = {x + (3x/4)}/28 ⇒ 90 x 5/18 = (7x/4)/28 ⇒ x = 400 m Therefore, let the length of the platform be y metre ⇒ 60 x 5/18 = (400 + y)/36 ⇒ 600 = 400 + y ⇒ y = 600 – 400 = 200 m
Statements:
Z ≤ Y < E < I; O > P > V > Q = I;
Conclusions:
I) Y > O
II) Q > Z
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