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Let the length of the first train is x metre Length of second train = 3x/4 Therefore, (60 + 30) x 5/18 = {x + (3x/4)}/28 ⇒ 90 x 5/18 = (7x/4)/28 ⇒ x = 400 m Therefore, let the length of the platform be y metre ⇒ 60 x 5/18 = (400 + y)/36 ⇒ 600 = 400 + y ⇒ y = 600 – 400 = 200 m
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