Train P travelling at 50 km/hr crosses another train Q, having three fourth of its length and travelling in opposite direction at 40 km/hr in 14 seconds. Train P passed a railway platform in 36 seconds. Find the length of platform.
Let the length of the first train is x metre Length of second train = 3x/4 Therefore, (50 + 40) x 5/18 = {x + (3x/4)}/14 ⇒ 90 x 5/18 = (7x/4)/14 ⇒ x = 200 m Therefore, let the length of the platform be y metre ⇒ 50 x 5/18 = (200 + y)/36 ⇒ 500 = 200 + y ⇒ y = 500 – 200 = 300 m
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